2m^2+4m=16

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Solution for 2m^2+4m=16 equation:


Simplifying
2m2 + 4m = 16

Reorder the terms:
4m + 2m2 = 16

Solving
4m + 2m2 = 16

Solving for variable 'm'.

Reorder the terms:
-16 + 4m + 2m2 = 16 + -16

Combine like terms: 16 + -16 = 0
-16 + 4m + 2m2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(-8 + 2m + m2) = 0

Factor a trinomial.
2((-4 + -1m)(2 + -1m)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(-4 + -1m)' equal to zero and attempt to solve: Simplifying -4 + -1m = 0 Solving -4 + -1m = 0 Move all terms containing m to the left, all other terms to the right. Add '4' to each side of the equation. -4 + 4 + -1m = 0 + 4 Combine like terms: -4 + 4 = 0 0 + -1m = 0 + 4 -1m = 0 + 4 Combine like terms: 0 + 4 = 4 -1m = 4 Divide each side by '-1'. m = -4 Simplifying m = -4

Subproblem 2

Set the factor '(2 + -1m)' equal to zero and attempt to solve: Simplifying 2 + -1m = 0 Solving 2 + -1m = 0 Move all terms containing m to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1m = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1m = 0 + -2 -1m = 0 + -2 Combine like terms: 0 + -2 = -2 -1m = -2 Divide each side by '-1'. m = 2 Simplifying m = 2

Solution

m = {-4, 2}

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